Theorem: The angle of intersection of two lines and their inverse images

Statement

Let K be a circle and [Maple Math] and [Maple Math] be lines that intersect at point C.

The angle of intersection of [Maple Math] and [Maple Math] at point C is the same as the angle of intersection of their inverse images with respect to circle K.

Diagram

[Maple Metafile]

Proof

Let the circle [Maple Math] be the inverse of [Maple Math] .

Let the circle [Maple Math] be the inverse of [Maple Math] .

Both [Maple Math] and [Maple Math] pass through the center of circle K, point O.

Let [Maple Math] be the foot of the perpendicular segment from O to line [Maple Math] .

Let [Maple Math] be the foot of the perpendicular segment from O to line [Maple Math] .

Note that [Maple Math] contains the center of [Maple Math] , and [Maple Math] contains the center of [Maple Math] .

Let [Maple Math] be the tangent to circle [Maple Math] , and [Maple Math] be the tangent to circle [Maple Math] .

Then [Maple Math] is perpendicular to [Maple Math] , and [Maple Math] is perpendicular to [Maple Math] .

But, [Maple Math] is also perpendicular to [Maple Math] , so [Maple Math] is parallel to [Maple Math] .

Similarly [Maple Math] is perpendicular to [Maple Math] , so [Maple Math] is parallel to [Maple Math] .

So, angle APB, the angle of intersection of the two lines, is equal to angle A'OB', the angle of intersection of their inverse images with respect to K.

Q.E.D.

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